Question

An electric current 100 ampere is passed through a molten liquid of sodium chloride for 5 hours. Calculate the volume of chlorine gas liberated at the electrode at ntp.

Answer 1

Answer : The volume of chlorine gas liberated at the electrode at NTP will be, 208.9 L

Solution :

The reaction taking place at anode will be,

$2Cl^-\rightarrow Cl_2+2e^-$

Formula used :

$Q=I\times t=100\times 5\times 60\times 60=18\times 10^5\text{ coulomb}$

The amount of chlorine liberated by passing $18\times 10^5\text{ coulomb}$ of electric charge = $\frac{1}{(2\times 96500)}\times 18\times 10^5\text{ coulomb}=9.326mole$  

Volume of $Cl_2$ liberated at NTP = $9.326\times 22.4=208.9L$

Therefore, the volume of chlorine gas liberated at the electrode at NTP will be, 208.9 L