Question

An electric current flowing through a resistance coil of 41.812 produces 600 ca
of 41 80 produces 600 cal/minute. Find the
current through the coil [J = 4.18 J/cal].​

Answer 1

Explanation:

as per joules law

heat produced = i^2 * R * t

600*4.18/60 = i^2 * 41.8

10*4.18/41.8 = i^2

i^2 = 1

i = 1 A