Chemistry, asked by vaichaku3758, 1 year ago

an electric current is passed through silver voltmeter connected to a water voltameter. the cathode of silver voltameter weighed 0.108gm more at the end of eleçtrolysis the volume of O2 at STP evolved is

Answers

Answered by danielochich
45
Ag+ + e = Ag

1 mole of electrons deposit 1 mole of Ag

Relative atomic mass of Ag = 108

Moles of e = 0.108/108 = 0.001 moles




4OH-1(aq) = 2H2O(l) + O2(g) + 4e

4 moles of e are released when one mole of O2 is liberated

0.001 moles of e ≡ 0.001/4 = 0.00025 moles of O2


Molar gas volume at STP = 22400 ml

Volume of O2 = 22400 x 0.00025

                      = 5.6 ml




Answered by Anonymous
12

Answer:

Explanation:

Ag+ + e = Ag

1 mole of electrons deposit 1 mole of Ag

Relative atomic mass of Ag = 108

Moles of e = 0.108/108 = 0.001 moles

4OH-1(aq) = 2H2O(l) + O2(g) + 4e

4 moles of e are released when one mole of O2 is liberated

0.001 moles of e ≡ 0.001/4 = 0.00025 moles of O2

Molar gas volume at STP = 22400 ml

Volume of O2 = 22400 x 0.00025

= 5.6 ml

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