an electric current of 2A passes through a wire of resistance of 25 ohm heat will be developed in 1 min
Answers
Heat =( Current flowing)² × Resistance of wire × Time taken
Heat = 4 ×25 × 60 sec
Heat = 6000joule
Concept:
The energy dissipated by a component or circuit can be estimated by adding time (t) to the power equations. Energy (power × time) is measured in Joules. Mathematically, it is expressed as, H = I²Rt
Given:
Electric current, I = 2A
Resistance, R = 25 ohms
time, t = 1min = 60 seconds
Find:
We need to determine the Heat, H.
Solution:
When an electric current flows through a conductor, heat is produced, making the conductor hot. This is the electric current's heating impact also known as the heating effect of electric current. When a potential difference is applied across a conductor, flow of electrons take place. This electrons may collide with each other and other atoms and thus gives rise to resistance of the conductor. To overcome this resistance, work must be done. This work done is converted to heat.
Work, W = V²t/R where. V = potential difference, t = time and R = resistance
We know, V = IR
Therefore, Heat, H = I²RT where I = current
H = 2²×25×60
H = 6000 Joules.
Thus, the heat developed when an electric current of 2A passes through a wire of resistance of 25 ohm is 6,000 J.
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