An electric current of 5 A is passing through a circuit containing three wires of same material
arranged in parallel. If the length and the radius of
the wires are in ratio 2:3:4 and 3:4:5
respectively, then the ratio of current passing
through the wires would be
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R=Aρl
⟹ R∝Al
R1:R2:R3=92:163:254
As the wires are connected in parallel, so I∝1/R
I1:I2:I3=9/2:16/3:25/4=54:64:75
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