Question

an electric current of 5a is divided into 3 branches length of wires 1:2:3 find the current in each branch

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Answer 1

Answer:So current in first wire would be  = 30/11 A

Current in second wire  = 15/11 A

Current in third wire = 10/11 A

Explanation:

As we know the resistance of the resistor is directly proportional to its length

So let us assume the resistance of the first wire to be R then resistance of the second wire is 2R and resistance of third wire is 3R

In question it is not given that resistor are connected in parallel or series. I am assuming it is connected in parallel.

Let's say the voltage to be V

Current in first wire = V/R

Current in second wire =  V/2R

Current in third wire = V/3R

So here we can see current is inversely proportional to resistance of the wire that means lowest resistance will have higher current and higher resistance will have lowest current  

So current in first wire would be  = 30/11 A

Current in second wire  = 15/11 A

Current in third wire = 10/11 A