Question

An electric device delivers a current of 5.0 a to a device. How many electrons flow through this device in 10 s?

Answer 1

Answer:3.125 x 10^20 electrons

Explanation:We know,

I = Q/T

Therefore,

5= Q/10

Q= 50C

We know that,

1C = 6.25 x 10^18 electrons

Therefore,

50C = 6.25 x 5 x 10 x 10^18 electrons

=3.125 x 10^20 electrons

Answer 2

Answer:

$3.125\times10^{20}$ electrons will flow through the device in 10 seconds.

Explanation:

Value of given current = 5A

Total time given  = 10 seconds

Now, we have to calculate the charge

As we know that

$\[\begin{gathered} I = \frac{q}{t} \hfill \\ q = I \times t \hfill \\ q = 5 \times 10 \hfill \\ q = 50C \hfill \\ \end{gathered} \]$

Now, calculate the number of electrons in the 50C charge.

Charge on one electron = $1.6\times10^{-19}C$

So, the number of electrons in 1C = $\frac{1}{1.6\times10^{-19}}$

The total number of electron in 1C = $6.25\times10^{18}$ electrons

Total number of electrons in 50C = $6.25\times10^{18}\times50$

Total number of electrons in 50C = $3.125\times10^{20}$ electrons

Therefore, $3.125\times10^{20}$ electrons will flow through the device in 10 seconds.