An electric device works properly if P.D across it is 110V , when the current is found to be 2.4A. what resistance must be connected in series if it is to run on 230V source?
Answers
Explanation:
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Question :----- we have to find what resistance must be connected in series to work it safely ....
Given:----------
potential difference = 110V
current = 2.4 A
After that 230V of PD applied .
Solution :-----
we know that resistance is the opposition to current flow.
According to Ohm's Law the relationship between the voltage (V), current (I) and resistance (R) is :--------
V = I × R
So,
R = V/I
R = 110/2.4 = 1100/24 = 275/6 = 45.833 Ω
Now, By voltage division Formula we know that,
V/(R1+R2) = Safety current ,
Given New V = 230V , Safety current = 2.4 , R1 = 45.833 Ω
Putting all values now , we get,
230/(45.833+R2) = 2.4
→ 230/2.4 = 45.833 + R2
→ 2300/24 = 45.833 + R2
→ 575/6 = 45.833 + R2
→ 95.833 = 45.833 + R2
→ R2 = 95.833 - 45.833
→ R2 = 50 Ω
So, 50 Ω Resistance is Required in series to work it safely.