Question

an electric dipole consist of two charges+2Cand-2C separate by a distance 4cm between them find its,1)dipole moment and(2)electric field an axial point distance 40 m from the centre of the dipole​

Answer 1

Answer:

Dipole moment = .08 Cm

Potential at axial point = .045 x $10^{13}$ V

Explanation:

Q = 2 C

2a = 4 cm = .04 m

P = 2a x Q                   (P is dipole moment

   = .04 x 2                   2a is distance between the charges

   = .08 Cm                   Q is the charge)

Potential due to a dipole = $\frac{K P Cosx}{r^{2} }$

x = 0 degrees, axial

$V = \frac{K P}{r^{2} }$

   = 9 x $10^{9}$ x .08 / 16 x$10^{-4}$

   = .045 x $10^{13}$ V