Question

an electric dipole consisting of a pair of equal and opposite charges each of magnitude 5uC has dipole moment equal to 5.0×10^-7 Cm . Find the length of the dipole.​

Answer 1

Answer:

p= q×l

here p- dipole moment

l = length of dipole

by this formula we get l= 10 cm

Answer 2

Given:

• The magnitude of the charges = 5 μC = 50 C
• Dipole moment = 5.0 × $10^{-7}$ cm

To Find:

• The length of the dipole.

Solution:

We know that " dipole moment = magnitudes of charges × distance between them (length)"

⇒ p = q × l → {equation 1}

Where "q" is the charge, "l" is the length of the dipole, and "p" is the dipole.

Rearrange equation 1 to find the length of the dipole.

⇒ l = p/q

On substituting the given values in the above equation we get,

⇒ l = 50/5 { dividing the terms}

⇒ l = 10 = 0.1 m

∴ The length of the dipole is 0.1m