An electric dipole consisting of charge 5 micro coulomb and - 5 micro coulomb and of length 10cm. what is the total electric flux through the box?
jashan1291:
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Dear Student,
● Answer -
Net electric flux = Zero
◆ Explaination -
For a closed surface, total electric flux is equal to the net charge enclosed divided by the permittivity.
Φ = Q / ε
Net charge enclosed in the box -
Q = q1 + q2
Q = (+5) + (-5)
Q = 0
Thus, electric flux will be -
Φ = 0 / ε
Φ = 0
Therefore, electric flux paasing through the box enclosing the electric dipole will be zero.
Thanks for asking..
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