An electric dipole consists of two charges + 10 UC and -10 UC separated by a distance of 5 mm. Calculate the electric field at a point on the axial line due to the dipole at a distance of 10 cm from the centre of the dipole?
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Answer:
9×10^5
Explanation:
E=[2P÷r^3]×9×10^9
2a<<<<<r
P=q×2a
=10×10^-6×5×10^-3=5×10^-8
E=[2×5×10^-8÷(0.1)^3×9×10^9=1.5×10^-23
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