An electric dipole consists of two charges of 0.1 micro columb separated by a distance of 2.0 cm the dipole is placed in an electric field of 10 power 5 N/C . What is the maximum torque does the field exerts on the dipole
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Answer:
An electric dipole consists of two charges of
separated bu a distance of
. The dipole is placed in an external field of
. What maximum torqur does the field exert on the dipole?
Answered by
1
Answer:
0.2 x 10^(-3) or 2 x 10^(-4) Nm
Explanation:
Dipole moment(p) = 2lq = dq
Dipole moment = (2cm)(0.1u C)
Dipole moment = 0.2 x 10^(-8) C m
Electric field(E) = 10^(5) N/C
Using torque = p x E (vector product)
=> torque = pEsin∅
For torque to be maximum, sin∅ must be maximum i.e. 1.
=> max. torque = pE(1)
=> max. torque = 0.2 x 10^(-8) × 10^(5)
=> max. torque = 0.2 x 10^(-3) Nm
Note that: if charges are 1u C & not 0.1u C and E is 10^(-5) N/C & not 10^(5), then the answer is 2 x 10^(-12).
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