An electric dipole consists of two charges
of equal magnitude and opposite signs separated by a
distance 2a as shown in figure. The dipole is along the
X-axis and is centred at the origin.
Answers
Answer:
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Explanation:
Let, dipole of the K. B at point where +a charge and P at a point,
E
1
=
K(BP)
2
9
=
K(x−a)
2
9
(E
1
, towards
OP
)
and, A at a point −9 charge where the electric field at point P
E
2
=
K(AP)
2
9
=
K(x+a)
2
9
(E
2
, towards
PO
)
Since, E
1
and E
2
are same line but opposite in direction and E
1
>E
2
∴ P at a point,
The resultant of electric field P.
E=E
1
−E
2
=
K
9
[
(x−a)
2
1
−
(x+a)
2
1
]
=
K
9
[
(x−a)
2
(x−a)
2
(x+a)
2
−(x−a)
2
]
E=
K(x
2
−a
2
)
2
9.4xa
=
K(x
2
−a
2
)
2
2px
[∵P=2aq]
Calculation at V at a point four from the dipole
V=
q
E
=
Kq(x
2
−a
2
)
2
2px