Question

An electric dipole consists of two equal and opposite charges +150 µ C and -150 µC separated by a
distance of 10cm. Calculate the electric field due to the dipole at a distance of 15 cm from each charge.

Answer 1

Answer:

3.42×10^7N/C

Explanation:

As the point is equidistant from both the charges, the point is probably situated on the equatorial line.

Let distance between the point and the centre of dipole be=r

$r = \sqrt{ {15}^{2} + {5}^{2} } = 5 \sqrt{10} cm$

E=kp/(r) ^3

where, k=1/4(pi)(permittivity of free space)=9×10^9

p=dipole moment

E=9×10^(9)×150×10^(-6)×0.1/(5×10^(1/2)×10^(-2))^3

E=3.42×10^7N/C

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If it's too clumsy, just see the image I provided. It has the diagram and the process I did.