Question

An electric dipole consists of two opposite charges each of magnitude 8 nC seperated by 8.0cm. The dipole is placed in an external field of 5×10^5N/C. What maximum torque will the field exert on the dipole?

Answer 1

Answer:

1. 32×10^6

Explanation:

PE=torque ....use and solve

Answer 2

Answer:

Max Torque = 320×10^-6 Nm

Explanation:

Given,

q = 8×10^-9 C

d = 8×10^-2 m

E = 5×10^5 N/C

Torque = pEsinø

Torque(max) » sinø = 1

Torque = pE

= qdE

= (8×10^-9)(8×10^-2)(5×10^5)

= 64×5×10^-6

= 320×10^-6 Nm