Question

An electric dipole consists of two unlike charges of magnitude 1.6 x 10-19 C. separated by

2 A°

. If the dipole is placed in a uniform electric field of 10 N/C, making an angle of 30o with the

dipole moment, the potential energy of the dipole is?​

Answer 1

Answer:

Dipole moment P=qd

So, P=1.6×10

−19

×10

−10

=1.6×10

−29

C−m

Explanation:

This may help you

Answer 2

Solution:

General Expression for Potential Energy of a Dipole in an Electrostatic Field is :

$E_{P} = - PE \cos( \theta)$

• 'P' is dipole moment, 'E' is Electrostatic Field Intensity.

$\implies E_{P} = - (q \times d)E \cos( \theta)$

$\implies E_{P} = - (1.6 \times {10}^{ - 19} \times 2 \times {10}^{ - 10} )10\cos( {30}^{ \circ} )$

$\implies E_{P} = - (1.6 \times {10}^{ - 19} \times 2 \times {10}^{ - 10} ) \times 10 \times \dfrac{ \sqrt{3} }{2}$

$\implies E_{P} = - 3.2 \times {10}^{ - 28} \times \dfrac{ \sqrt{3} }{2}$

$\implies E_{P} = - 2.77 \times {10}^{ - 28} \: joule$

So, magnitude of potential energy is 2.77 × 10^(-28) Joule .