Question

An electric dipole having two opposite charges each of 3 microcoulomb separated by 4 cm is placed in a uniform electric
field of 3.0×10^4 NC^-1 . Calculate

(a) maximum torque acting on the dipole. (b) the work done to turn the dipole
in the opposite direction.

Don't spam​

Answer 1

Answer:

An electric dipole consist at two opposite charge each of magnitude =1μC=1×10  

−6

C

distance =2cm

Exter field =10  

5

N/C

maximum torque on the dipole =?

q=1×10  

−6

C,2a=2cm

                               or,  =0.02cm

∴    P=q×2a

          =(1×10  

−6

)×0.02

          =2×10  

−8

cm

Intensity of the external electric field, E=1.0×10  

5

N/C

(i) Z  

max

​  

=pE=(2×10  

−8

)(10×10  

5

)=2×10  

−3

N−m

(ii) Net work done in turning the dipole from 0  

0

 to 180  

0

 

i.e  W=∫  

0  

0

 

180  

0

 

​  

 

r

dθ=∫  

0  

0

 

180  

0

 

​  

pEsinθdθ

          =pE[−cosθ]  

0  

0

 

180  

0

 

​  

 

          =−pE(cos180  

0

−cos0  

0

)

          =2pE

          =2×(2×10  

−8

)(1×10  

5

)J

          =4×10  

−3

J

Explanation: