Question

an electric dipole held at an angle of30 degree with respect to a inform electric field of 4 into 10 ki power 4 newton bi kulam experiences torque of 1.6 into 10 ki power minus 25 Newton metre calculate its dipote moment

Answer 1

Let the distance between the charges q and -q in the dipole, be 2a.
Ф = angle between electric field E and dipole. = 30°.
E = 4 * 10⁴ N/C
F = force on each charge = q E
Torque = 1.6 * 10⁻²⁵ Nm
Dipole moment = P = 2 a q

Torque on dipole = 2 | r X F | = 2 a F SinФ 
          =  2 a q E sinФ 
          = P E sinФ
   1.6 *10⁻²⁵ = P * 4 * 10⁴ * sin30°

   P = 8 * 10⁻³⁰ Coul-meter

Answer 2

Let the distance between the charges q and -q in the dipole, be 2a.

Ф = angle between electric field E and dipole. = 30°.

E = 4 * 10⁴ N/C

F = force on each charge = q E

Torque = 1.6 * 10⁻²⁵ Nm

Dipole moment = P = 2 a q

Torque on dipole = 2 | r X F | = 2 a F SinФ 

          =  2 a q E sinФ 

          = P E sinФ

   1.6 *10⁻²⁵ = P * 4 * 10⁴ * sin30°

   P = 8 * 10⁻³⁰ Coul-meter

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