Question

an electric dipole is placed at an alignment 30 with an electric field of 2×10^5 NC^-1.the charge on the dipole if the dipole length is 1 cm is​

Answer 1

Answer:

Here dipole moment , p=lq=(2/100)q=0.02q

Now, torque , τ=pEsinθ

or 4=(0.02q)(2×10

5

)sin30

or q=200×10

−5

C=2mC