Question

An electric dipole is placed at an alignment angle of 30 ° with an electric field of 2×10^5.It experiences a torque equal to 8 Nm. The charge on the dipole length is 1 cm is

Answer 1

$\huge \underline \green{\sf{ Answer :- }}$

$\small \underline {\sf{Here \ dipole \ moment , p=lq=(2/100)q=0.02q }}$

• $\small \underline {\sf{ Now, \ torque , τ=pEsinθ}}$

• $\small \underline {\sf{ or 4=(0.02q(2×105)sin30}}$

• $\small \underline {\sf{or 4=(0.02q(2×105)sin30 }}$

Answer 2

Answer:

Here dipole moment, p=lq=(2/100)q=0.02q

\small \underline {\sf{ Now, \ torque , τ=pEsinθ}}

Now, torque, τ=pEsinθ

\small \underline {\sf{ or 4=(0.02q(2×105)sin30}}

or 4=(0.02q(2×105)sin30

\small \underline {\sf{or 4=(0.02q(2×105)sin30 }}

• or 4=(0.02q(2×105)sin30

Explanation:

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