an electric dipole is placed at an alignment angle of 30 degree with an electric field of 2*10^5 NC^-1. It experiences a torque equal to 8Nm. The charge on the dipole if the dipole length is 1cm is?
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Answer:
τ = PEsinθ
τ =qlE sin θ
4=q×2×10^-2×2×10^5sin30°
q=2mC
Explanation:
not sure
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