Physics, asked by DIPAN8952, 1 year ago

An electric dipole moment 4 x 10^-9 cm is kept at 30° with the direction of uniform electric field of magnitude 5 x 10^4nc^-1.The magnitude of torque on the dipole is

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Answered by LALITMOHANMUNJAL
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Answered by Anonymous
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Electric dipole moment, p = 4 × 10−9 C m (Given)

Angle made by p with a uniform electric field, θ = 30° (Given)

Electric field, E = 5 × 104 N C−1 (Given)

Torque acting on the dipole is given by the relation,

τ = pE sinθ

= 4 × 10-9 × 5 × 104 × sin 30

= 20 × 10-5 × 1 half

= 10-4 Nm

Therefore, the magnitude of the torque acting on the dipole is 10−4 N m.

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