Question

An electric dipole moment 4x10^-9 cm is kept at 30° with the direction of uniform electric field of magnitude 5 x 10^4nc^-1.The magnitude of torque on the dipole is

Answer 1

Hola User_________

Here is Your Answer..!!!
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↪Actually welcome to the concept of the E LECTROSTATICS..

↪Basically the Torque of a dipole moment kept in a external electric field is given by

↪TORQUE ( tau ) = P .E .Sin@

↪since here , P = 4 × 10^-9 , E = 5 × 10^4 , and @ = 30°

↪thus substituting we get as..

↪T = P.E sin 30°

↪thus T = ( 4 × 10^-9) ( 5 × 10^4 ) ( 1/2)

↪so we get as ...

↪T = 20 × 1/2 × 10^-5

↪solving we get as ...

↪TORQUE (T) = 10. 10^-5 ==== 10^-4

↪therefore torque = 10^-4 Units

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↪⭐Hope it helps u...☺

Answer 2

Hey !
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$= > an \: electric \: dipole \: movement \: 4 \times 10 {}^{ - 9} \: is \: kept \: at \: 30 \: degree \\ \: with \: the \: direction \: of \: uniform \: electric \: field \: of \: magnitude \\ \: 5 \times 10 {}^{4} nc {}^{ - 1} .the \: magnitude \: of \: torque \: on \: \: the \: dipole \: is \:$

→We need to find the Torque on the dipole . So the formula for calculating the Dipole is given by :

=> Torque = P•E • Sin ∅

⚫Here ,

♦P = 4 × 10^-9

♦E = 5 × 10⁴

♦Angle ∅ = 30°

~Putting in formula =>
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=> T = 4 × 10^-9 × 5 × 10⁴ × Sin 30°

=> T = 20 × 10^-5 × ½ [ Sin 30° = 1/2 ]

=> T = 10 × 10^-5

=> T = 10^-4 units

▪→Hence the Torque acting on the Dipole is 10^-4 units !!

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