an electric dipole of dilole moment 20×10^-6 C m is enclosed by a closed surface .What is the net flux coming out of this surface.
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In my opinion, it's answer should be zero because flux lines are originated from positive charge and sink on negative charge.
No matter what the dipole moment is. Since a dipole contains both, positive and negative charge, flux will originate from positive charge and sink on negative charge and since both charges are inside the closed surface , the net flux crossing the surface should be zero.
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Answer:
clearly p = 20×10^-6 Cm
q×2a = 20×10^-6
net charge enclosed in a closed surface is 0
hence net flux will be 0
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