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An electric dipole of dipole moment 60 × 10–6 C m is enclosed by a closed surface. The net electric flux through the surface is​

Answers

Answered by athirakrishnan783
0

Answer:

Explanation:

From gaussion law, flux is given by, ϕ =  ​ qinc / ε0

​ and we know that a dipole has both −ve as well as +ve charge of equal magnitude.

this implies that the total enclosed charge is given by,

​ qinc = 0

∴ Ф = 0 / ∈0 = 0

∴ There will be no flux through the surface ( or )  Net electric flux coming out of closed surface is zero

Answered by thakrepayal
0

An electric dipole of dipole moment 60 × 10–6 C m is enclosed by a closed surface. The net electric flux through the surface is​..

From gaussion law, flux is given by, ϕ =  ​qinc / ε0

and we know that a dipole has both −ve as well as +ve charge of equal magnitude.

this implies that the total enclosed charge is given by,

​qinc = 0

∴ Ф = 0 / ∈0 = 0

∴ There will be no flux through the surface ( or )  Net electric flux coming out of closed surface is zero.

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