An electric dipole of dipole moment 60 × 10–6 C m is enclosed by a closed surface. The net electric flux through the surface is
Answers
Answer:
Explanation:
From gaussion law, flux is given by, ϕ = qinc / ε0
and we know that a dipole has both −ve as well as +ve charge of equal magnitude.
this implies that the total enclosed charge is given by,
qinc = 0
∴ Ф = 0 / ∈0 = 0
∴ There will be no flux through the surface ( or ) Net electric flux coming out of closed surface is zero
An electric dipole of dipole moment 60 × 10–6 C m is enclosed by a closed surface. The net electric flux through the surface is..
From gaussion law, flux is given by, ϕ = qinc / ε0
and we know that a dipole has both −ve as well as +ve charge of equal magnitude.
this implies that the total enclosed charge is given by,
qinc = 0
∴ Ф = 0 / ∈0 = 0
∴ There will be no flux through the surface ( or ) Net electric flux coming out of closed surface is zero.