Question

an electric dipole of dipole moment
$20 \times {10}^{ - 6}$
Cm is enclosed by a closed surface what is the net flux coming out of the surface?

Answer 1

The net flux through a surface can be found by considering a closed Gaussian surface enclosing the charges. The flux is equal to the net charge divided by ε0.

In the question, the enclosed by a Gaussian surface due to the dipole is = +q + (-q) = 0

Therefore, the flux is, ϕ = 0/ε0 = 0