Question

an electric dipole of length 10 cm placed at an angle of 30° with a uniform electric field of intensity 3*10^5 n/c experiences a torque of magnitude 5*10^-5 nm. calculate the dipole moment and magnitude of electric charge.
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Answer 1

Answer:

q = 0.3× 10⁹

Explanation:

τ = P×E

5*10⁻⁵ = P*3*10⁵sin(30º) = P*3*10⁵*1/2

P = 1/3*10⁻⁹

and p = q×r = q× 0.1 = 1/3*10⁻⁹

so, q = 0.3× 10⁹

Answer 2

Answer:

Answer of this question is q=0.3×10^9