Question

an electric dipole of length 2.0 cm is placed with an Axis making an angle of 30° with a uniform electric field of
${10}^{5}$
N/C. If a dipole experiences a torque of
$10 \sqrt{3}$
Nm, calculate the magnitude of charg on a dipole​

Answer 1

Answer:

Dipole moment (p)=q.d=(6×10

−3

).0.1=6×10

−4

Cm

Torque(τ)=p×E=pEsinθ=6

3

Nm

⇒(6×10

−4

)×E×sin30

0

=6

3

⇒E=2

3

×10

4

N/C

Now, Potential Energy =

p

.

E

=pEcosθ=(6×10

−4

)×(2

3

×10

4

)×cos60

0

=18J

Explanation:

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Answer 2

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