An electric dipole of length 2 cm is placed in a uniform electric field of 105/ at an angle of 30. It experiences a torque of 10√3 , calculate the magnitude of charge on dipole.
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An electric dipole of length 2 cm is placed with its axis at an angle of 30° to a uniform electric field of 105 N/C. It experiences a torque of 10√3 N-m.
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Answer:
torque=P(dipole moment)×E(electric field)=PEsin(theta)
where theta is angle between dipole and field
P=charge×length
use formula and do yourself bro because only then you will remember
Explanation:
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