Question

An electric dipole of length 2 cm is placed with its
axis making an angle of 30° to a uniform electric
field 105 N/C. If it experiences a torque of
10/3 Nm, then potential energy of the dipole
​

Answer 1

Torque= PESin theta

10/3 = P × 105 × Sin30°

10/3 = P × 105 × 1/2

3.33 = P × 52.5

P = 3.33/ 52.5

P = 0.06 Cm

U= - pE Cos theta

U = - 0.06 × 105 × root3/2

U = -5.4J