Question

An electric dipole of length 2 cm is placed with its axis making an angle of 60⁰ with respect to uniform electric field of 105 NC-1 . If it experiences a torque of 8√3 Nm, calculate the magnitude of charge on the dipole and its potential energy​

Answer 1

Answer: Torque acting on a dipole = p E sin(theta)

13.856 = q * 0.02 * 105 * sin 60

q = 13.856 *2/105 * root 3 * 0.02 = 7.618c