Question

An electric dipole of length 20 cm having +3x103 C charge placed at 60° with respect to a uniform
electric field experiences a torque of magnitude 6 Nm. The potential energy of the dipole is
(B) 573J
(A) -2/3J
(C) -32J
(D) 35J​

Answer 1

Answer:

(C) -32J

Explanation:

I hope it's helpful

Answer 2

ANSWER: B -2√3 j

explanation:

Here length of dipole 2a=20cm=20×10 −2

m, Charge q=±3×10 −3 C,θ=60°

and torque τ=6Nm

As τ=pEsinθ

E= psinθ

τ = q(2a)sin. (∵p=q(2a))

___________6____________

∴E= 3×10 −3 ×20×10 −2 ×sin60°

=10^5/5√3 NC-1

Potential energy of dipole U=−pEcosθ=−q(2a)Ecosθ

=−3×10 −3 (20×10 −2)10^5/5√3cos 60°

=-2√3 j