Question

An electric dipole of length 2cm and each charge
8 x 10-3c is placed with its axis making an angle 60° to
a uniform electric field of 10^5N/C. The potential energy
of dipole is

1)-8J 2)-6J 3) +8J 4) +6J​

Answer 1

Explanation:

Torque, τ=PEsin θ=2Qlsin θ

Here l is the length of the dipole, Q is the charge and E is the electric field.

Potential energy, U=−PEcos θ=−2Qlcos θ

Uτ=−2Qlcosθ2Qlsinθ     (where P=qd)   =−tanθUτ=−tanθU=−tan 600τ=−383=−8 joule

Answer 2

Answer:

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