Question

An electric dipole of length 4 cm when placed with its axis making an angle of 60 degree with a uniform electric field experiences torque of 4v3n-m calculate the potential energy of the dipole if it has charge +-8nc

Answer 1

Answer:

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Answer 2

Given :

Length of electric dipole , l = 4 cm = 0.04 m .

Angle between dipole and electric field , $\theta=60^o$ .

Torque , $\tau=4\sqrt 3\ N.m$ .

Charge on electron , q = 8 nC .

To Find :

The potential energy of the dipole .

Solution :

We know , torque is given by :

$\tau=E(ql)sin\ \theta$

Putting all the values we get :

$4\sqrt 3=E(8\times 10^{-9}\times 0.04)\times sin\ 60^o\\\\E=\dfrac{4\sqrt 3}{8\times 10^{-9}\times 0.04\times sin\ 60^{\circ}}\\\\E=2.5\times 10^{10}\ N/C$

Now , potential energy is given by :

$P=-(ql)E\ cos\ \theta\\\\P=-8\times 10^{-9}\times 0.04\times 2.5\times 10^{10}\times 0.5\\\\P=-4\ J$

Learn More :

Electrostatics

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