Question

An electric dipole ,when held at 30° write uniform electric field of 10^4 N/C experience torque of 9×10^-26Nm. Calculate the dipole moment of the dipole

Answer 1

Answer:

• The Dipole Moment (P) is 18 × 10⁻³⁰ Cm

Given:

1. Electric field (E) = 10⁴ N/C
2. Torque (τ) = 9 × 10⁻²⁶ N-m
3. Angle (θ) = 30°

Explanation:

$\rule{300}{1.5}$

From the formula we know,

$\large\bigstar\;\underline{\boxed{\sf \tau = P E \sin \theta}}$

Here,

• τ Denotes Torque.
• P Denotes Dipole moment.
• E Denotes electric field.

Substituting the values,

$\longrightarrow\sf 9\times 10^{-26}=P\times 10^{4}\times \sin 30^{\circ} \\\\\\\longrightarrow\sf 9\times 10^{-26}=P\times 10^{4}\times \dfrac{1}{2}\\\\\\\longrightarrow\sf 9\times 2 \times 10^{-26}=P\times 10^{4}\\\\\\\longrightarrow\sf P=\dfrac{18\times 10^{-26}}{10^{4}}\\\\\\\longrightarrow\sf P=18\times 10^{-26-4}\\\\\\\longrightarrow\sf P=18\times 10^{-30}\\\\\\\longrightarrow \large{\underline{\boxed{\red{\sf P=18\times 10^{-30}\;Cm}}}}$

∴ The Dipole Moment (P) is 18 × 10⁻³⁰ Cm.

$\rule{300}{1.5}$

Answer 2

Answer:

The Dipole Moment (P) is 18 × 10⁻³⁰ Cm

Given:

Electric field (E) = 10⁴ N/C

Torque (τ) = 9 × 10⁻²⁶ N-m

Angle (θ) = 30°

Explanation:

$$\rule{300}{1.5}$$

From the formula we know,

$\large\bigstar\;\underline{\boxed{\sf \tau = P E \sin \theta}}$

Here,

τ Denotes Torque.

P Denotes Dipole moment.

E Denotes electric field.

Substituting the values,

$\begin{gathered}\longrightarrow\sf 9\times 10^{-26}=P\times 10^{4}\times \sin 30^{\circ} \\\\\\\longrightarrow\sf 9\times 10^{-26}=P\times 10^{4}\times \dfrac{1}{2}\\\\\\\longrightarrow\sf 9\times 2 \times 10^{-26}=P\times 10^{4}\\\\\\\longrightarrow\sf P=\dfrac{18\times 10^{-26}}{10^{4}}\\\\\\\longrightarrow\sf P=18\times 10^{-26-4}\\\\\\\longrightarrow\sf P=18\times 10^{-30}\\\\\\\longrightarrow \large{\underline{\boxed{\red{\sf P=18\times 10^{-30}\;Cm}}}}\end{gathered}$

∴ The Dipole Moment (P) is 18 × 10⁻³⁰ Cm.

$$\rule{300}{1.5}$$