Physics, asked by randheerkumarnain, 9 months ago

an electric dipole with dipole moment 4 *10-15C-m is placed at 30 degree with electric field of 10-3 N/C find torque on dipole?​

Answers

Answered by zahaansajid
3

Good Noon

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Here's your answer

ζ = pEsinθ

Here

p = 4×10⁻¹⁵

θ = 30°     =>  sinθ = sin30 = 1/2

E = 10⁻³

ζ = pEsinθ

ζ = 4×10⁻¹⁵×10⁻³×1/2

ζ = 2×10⁻¹⁸ Nm

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