Question

An electric fan has blades of length 30 cm as measured from the axis of rotation. If the fan is rotating at 1200 rpm, the acceleration of a point on the tip of the blade is about:

Answer 1

Angular acceleration of the fan, $a=1.70\times 10^7\ rad/s^2$

Explanation:

Given that,

Length of the blades, l = 30 cm = 0.3 m

Angular speed of the fan, $\omega=1200\ rpm=7539.82\ rad/s$

Let a is the acceleration of a point on the tip of the blade. Its expression is given by :

$a=\omega^2 r$

$a=(7539.82)^2 \times 0.3$

$a=1.70\times 10^7\ rad/s^2$

So, the acceleration of a point on the tip of the blade is about $1.70\times 10^7\ rad/s^2$. Hence, this is the required solution.

Answer 2

Answer:Use centripetal acceleration

Explanation: