Question

An electric fan is connected to a 220 V supply.It consumes a current of 500mA. Find the power of the bulb

Answer 1

Given :-

• Volt (V) = 220V
• Current (I) = 500mA

To Find :-

• The power(P) of the bulb.

Solution :-

As we know that,

↪ 1mA = 0.001000A

↪Current (I) ↪ 500mA ↪0.500000A.

We know that,

${ \boxed{ \red{ \tt{Power(P) = Volt(V) × Current(I)}}}}$

[ Putting values ]

↪ Power = 220 × 0.500000

↪ ${\boxed{\blue{\tt{Power = 110w.}}}}$

Hence,

• The power of the bulb is 110w.

Answer 2

$\star\:\:\:\bf\large\underline\blue{Given:–}$

➣Voltage of the electric fan,V = 220 V

➣Current, I = 500 mA = 0.5 A

$\star\:\:\:\bf\large\underline\blue{To\:find:–}$

Power of the bulb = ?

$\star\:\:\:\bf\large\underline\blue{Solution:–}$

As we know that,

$\boxed{\bf{\red{P=V×I}}}$

P = 220 × 0.5 watt

.°. P = 110 Watt

Hence, power of the bulb is 110 watt

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