Question

An electric feild given E=(40i+ 30j - 50k) N/C how much flux will pass through a rectangular surface of area 0.10 m^2 , placed in the region in such a way it is in Y-Z plane

Answer 1

Answer:

4m^2/C

Explanation:

E=(40i + 30j - 50k) N/C

electric flux = ? (

A = 0.10 m^2

since rectangular surface is in y - z plane, therefore plane vector will be in the x axis.

therefore, A = 0.10i m^2

Now according to formula,

electric flux = E.ds cos0°

= E.ds

=(40i + 30j -50 k).(0.10i)

= 40× 0.10

= 4 Nm^2/C Ans

hope this is your answer.