Question

An electric field e=20yj exist in space. the potential at (5m,5m) is taken to be zero. the potential at origin is

Answer 1

E = -dV/dx

dV = – Axdx

Integerating both sides,

V = -Ax^2/2 + c

at (10,20)

V = 0 => 150A = C

C = 1500

 

V at origin,

V  =  1500 V/m^2

Answer 2

Answer: The potential at origin is -250 V.

Explanation:

Given that,

Electric field $E = 20y\hat{j}$

Point P = (5 m,5 m)

The potential at origin is

$V=-\int_{x_{1}}^{x_{2}}(\vec{E}\cdot \vec{dl})$

$V = -\int_{5}^{0}(\vec{20 ydy)$

$V=-20(\dfrac{y^2}{2})_{0}^{5}$

$V=-250 V$

Hence, The potential at origin is -250 V.