An electric field is acting vertically upwards. A small body of mass 1 gram and charge -10^-6 C projected with a velocity 10m/s at an angle 45° with horizontal. It's horizontal range is 2m then the intensity of electric field is: (g=10m/s^2)
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Answer:
use electric field intensity formula.
Explanation:
E = F/q
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Answer:
40000 N/C this is the answer
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