an electric field of 200 volt per metre exist between the plates of parallel plate capacitor of separation between the plates 5 cm what is the potential difference between the plates then a dielectric slab of dielectric constant 4 and thickness 5 cm is inserted between the plates
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Answer:
Initial voltage=200V
q=C.V
q=
d
ϵ
0
.A
V (1)
When dielectric is inserted q remains constant and V decreases by k.
q=
d
′
+t−
k
t
ϵ
0
A
V (2)
From equation 1 and 2 we have,
d=d
′
+t−
k
t
d−d
′
=1.6mm=2−
k
2
solving,
k=5
Explanation:
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