An electric field of 3 x 10 is required to balance in air a liquid drop of mass 3 x 10^-4kg. yhe charge on drop is
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f (net) =ma
q . E = mg
q = (0.0003 × 9.8) ÷ 30
q = 0.000098 Coulomb
q . E = mg
q = (0.0003 × 9.8) ÷ 30
q = 0.000098 Coulomb
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