Question

an electric field of strength 50 voltmeter^-1 exist along the negative direction of y-axis . if one micro coulomb of positive charge is shifted from a point a(1m,-1m) to b(1m,3m)the work done by agent is​

Answer 1

Answer:

Here the x-component of electric field is given only, i.e E

x

=250V/m

Thus, E

x

=−

dx

dV

or V=−∫

0

0.2

E

x

dx (as x varies from x=0 to x=20cm=0.2m)

or V=−250(0.2)=−50V

The change in potential energy =qV=12×10

−6

×(−50)=−6×10

−4

J