Question

An electric flux of unit passes normally through a spherical gaussian surface of radius r,due to point charge placed at the center,what is the charge enclosed by gaussian surface?​

Answer 1

Answer:

Gauss's law states -

Net flux through a Gaussian surface (φ) = q/ɛ0. In this problem, given - flux = θ units, q = ?

Applying above theorem, q = ɛ0θ. Even if the radius of Gaussian surface is doubled, the flux passing through it remains the same as the charge enclosed has not changed. So, flux remains unchanged, i.e. θ units even when the radius is doubled.

Answer 2

Answer:

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Explanation:

When dipole moment vector is parallel to electric field vector.