Question

an electric flux over a sphere of radius 1m is
$\pi$
if radius of the sphere is doubled without changing the charge enclosed, electric flux will become​

Answer 1

Explanation:

flux will remain same. it will not change because flux depends on charge enclosed and permittivity of vaccum.

Answer 2

Answer:

π

Explanation:

Answer:

π

Explanation:

In this case π= q enclosed/∑0

where ∑0 is the permitivity in free space

π directly depends on q enclosed, since it does not change the electric flux remains the same