An electric fuse of rating 3A is connected in a circuit in which an electric iron of power 1 kW is connected which operates at 220 V What would happen? Explain.
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IF 3 AMPERES OF FUSE IS CONNECTED ACROSS THE ELECTRIC IRON OF POWER 1000 WATTS THE IT WILL MET IMMEDIATELY BECAUSE THE CURRENT THAT WILL FLOW IS 4.5 AMPERES .
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Answer:
power=potential difference*current
1kilo watt=1000watt
1000=220*i
1000/220=i
4.545454....=i
the fuse will met because the capacity of current is less to bear for the 3A current of wire
Explanation:
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