Question

An electric geyser consumes energy at a rate of
1000 watt, when heating is at the maximum rate.
And 500 watt, when the heating is at the minimum
rate. The voltage is 220 volt, what are the value of
the current and the resistance in each case?​

Answer 1

Explanation:

In maximum,

power=VI= V2/R

v is voltage, I is current, R is resistance

power=1000W

1000=220×I

I =1000/220

I =4.5A

1000=220×220/R

R=48.4 ohm.

In minimum,

power=500W

500=220×I

I=500/220

=2.2A

500=220×220/R

R=96.8 ohm.