Physics, asked by Nandini434P, 11 months ago

An electric geyser consumes energy at a rate of 1000watt when heating is at the maximum rate. And 500 watt when the heating is at the minimum rate. The voltage is 220Volt what are the value of the current and resistance in each case

Answers

Answered by chitrasaboo98
10

Explanation:

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Answered by niharikag53
23

Answer:

Here is your answer mate

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Explanation:

Case 1

When the heating is maximum

P = 1000w

V = 220v

We know that,

P = VI

1000=220×I

1000/220 = I

I = 4.45A

According to Ohm's law,

V = IR

220 = 4.45×R

220/4.45=R

R = 48.45 ohm

Case 2

When heating is minimum

Given :- P=500w

V = 220V

We know that,

P=VI

500=220× I

500/220= I

I = 2.27A

According to Ohm's law,

V=IR

220=2.27×R

220/2.27= R

R= 96.91ohm

Hope u understood

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