An electric geyser consumes energy at a rate of 1000watt when heating is at the maximum rate. And 500 watt when the heating is at the minimum rate. The voltage is 220Volt what are the value of the current and resistance in each case
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Explanation:
Case 1
When the heating is maximum
P = 1000w
V = 220v
We know that,
P = VI
1000=220×I
1000/220 = I
I = 4.45A
According to Ohm's law,
V = IR
220 = 4.45×R
220/4.45=R
R = 48.45 ohm
Case 2
When heating is minimum
Given :- P=500w
V = 220V
We know that,
P=VI
500=220× I
500/220= I
I = 2.27A
According to Ohm's law,
V=IR
220=2.27×R
220/2.27= R
R= 96.91ohm
Hope u understood
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